-(0,2x^2)+100x-10000=0

Solution for -(0,2x^2)+100x-10000=0 equation:

-(0.2x^2)+100x-10000=0

We add all the numbers together, and all the variables

100x-(0.2x^2)-10000=0

We get rid of parentheses

-0.2x^2+100x-10000=0

a = -0.2; b = 100; c = -10000;
Δ = b2-4ac
Δ = 1002-4·(-0.2)·(-10000)
Δ = 2000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2000}=\sqrt{400*5}=\sqrt{400}*\sqrt{5}=20\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-20\sqrt{5}}{2*-0.2}=\frac{-100-20\sqrt{5}}{-0.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+20\sqrt{5}}{2*-0.2}=\frac{-100+20\sqrt{5}}{-0.4}
$